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Re: 求助~~如何將字元轉成16進制的數值?
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版主
 
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1. 在C語言下可以使用 atoi ( ) 或 atol( ) 函數。
詳細使用方式請參 : C18 Libraries User'd Guide Function: Convert a string to a 16-bit signed integer. Include: stdlib.h Prototype: int atoi( const char * s ); Arguments: s Pointer to ASCII string to be converted. Remarks: This function converts the ASCII string s into an 16-bit signed integer (-32768 to 32767). The input string must be in base 10 (decimal radix) and can begin with a character indicating sign (‘+’ or ‘-’). Overflow results are undefined. This function is an MPLAB C18 extension to the ANSI standard libraries. Return Value: 16-bit signed integer for all strings in the range (-32768 to 32767). 2. 組合語言: 就須接收整個字串後將其還原成十進制(BCD)的碼後，再呼叫 BCD to HEX 的轉換程式。
發表於: 2006/4/10 15:42
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求助~~如何將字元轉成16進制的數值?
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新會員
 
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各位先進:
我利用PC經由RS232傳送"1234"的字串到PIC~ 要如何將這字串資料轉成16進制的"1234"的數值ㄋ...??? 有無範例程式提供給小弟參考~? 感恩喔~~
發表於: 2006/4/6 19:27
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