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Re: 请问,为什么只有RB3可以控制RE2的输出,RE3,RE4始终输出高电平
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高級會員
Joined
: 2008/5/1 22:02 最後登入時間
: 2012/9/7 10:21
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註冊會員
Level : 10 HP : 0 / 227 MP : 40 / 10887 EXP : 8
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會不會是你開了 watch dog , 還沒run到後面就 reset了
發表於: 2009/5/22 22:18
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请问,为什么只有RB3可以控制RE2的输出,RE3,RE4始终输出高电平
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新會員
Joined
: 2009/4/27 0:02 最後登入時間
: 2010/12/13 10:03
Group:
註冊會員
Level : 2 HP : 0 / 28 MP : 3 / 1272 EXP : 12
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#include "p30f4011.h" #include "adc12.h"
#define uint unsigned int #define uchar unsigned char void delay(uint t) { uint x,y; for(x=t;x>0;x--) for(y=614;y>0;y--); }
void initIO() { TRISE=0x00; LATE=0x00; ADPCFG=0XbF; _TRISB0=0; _TRISB1=0; _TRISB2=0; _TRISB3=1; _TRISB4=1; _TRISB5=1; LATB=0X07; TRISD=0XFF; TRISF=0X00; LATF=0; //LATB=0x07; // _RB0=1; // _RB1=1; // _RB2=1; // _RB3=0; // _RB4=0; // _RB5=0; // _LATB3=0; // _LATB4=0; // _LATB5=0; } void main() { uchar t=20; initIO(); _ADON=0; while(1) { if(_RB3==1) { t=20; while(t--); if(_RB3==1) { _RE2=1; } } else _RE2=0; if(_RB4==1) { t=20; while(t--); if(_RB4==1) _RE3=1; } else _RE3=0; if(_RB5==1) { t=20; while(t--); if(_RB5==1) { _RE4=1; } } else _RE4=0; } }
發表於: 2009/5/22 21:18
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