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Re: 請問乘法問題
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版主
 
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int main(void)
{ int ADC_Value1 = 0b100000000010, ADC_Value2 = 0b100000000010; long Result1; Result1= (long) ADC_Value1*ADC_Value2; while(1) ; Nop() ; } 加個強迫型別轉換 (long)
發表於: 2008/10/6 17:24
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Re: 請問乘法問題
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資深會員
 
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int 及 long int 是有正負號
你的值是 2050*2050=8196 00001000 00000010*00001000 00000010 =00000000 00000000 00100000 00000100 Watch看要拉開一點 我試了正常
發表於: 2008/10/4 14:36
Edited by maru2000 on 2008年10月04日 14:52:31
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 ^^   ^^ ====
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請問乘法問題
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新會員
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兩個16位元做乘法，應賅會產生32位元的值，
ex. 0000 1000 0000 0010 * 0000 1000 0000 0010 但為什麼Watch看到的卻沒有bit 17-31的值？ 程式碼如下： int main(void) { int ADC_Value1 = 0b100000000010, ADC_Value2 = 0b100000000010; long int Result1; Result1=ADC_Value1*ADC_Value2; while(1) ; Nop() ; }
發表於: 2008/10/4 11:45
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