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Re: 產生100次訊號
#3
版主
版主


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建議一下,真正細部的輸出 Timming,可以先用MPLAB SIM 先設好模擬的頻率後再用 Stopwatch 看執行的時間。

發表於: 2009/11/5 11:20
Twitter Facebook Google Plus Linkedin Del.icio.us Digg Reddit Mr. Wong 頂部


Re: 產生100次訊號
#2
高級會員
高級會員


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參照:

int main()
{
ADPCFG = 0xFFFF ;
TRISB = 0xFFFF ;
LATE = 0xFFFF;
TRISE = 0xFFF0;
int x;
for(x=0;x<100;x++)
{
LATEbits.LATE0 = 1;
delay(21);
LATEbits.LATE0 = 0;
delay(79);
}

while(1); //加上這行

}


我寫在引言裡,你加一行while()應該就搞定!
while(1); //加上這行

訊號會一直產生是因為一直被重置!

發表於: 2009/11/4 18:21
Morgan Chuang
s909201@gmail.com
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產生100次訊號
#1
新會員
新會員


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希望可以產生100訊號後停止,但用視波器觀察時,訊號不斷的產生,以下是我的程式碼,想請問有哪邊有問題

---------------------------------------------------------------------------------------------------------
#include <p30F4011.h>


#define FCY 7372800 * 2 // 因為使用頻率為將外部 7.3728 MHz * 8 的模式 , 每一指令週期需 4 個 clock
// 所以 FCY = (7.3728 * 8 / 4 ) MHz = 7372800* 2


_FOSC(CSW_FSCM_OFF & XT_PLL8); // XT with 8xPLL oscillator, Failsafe clock off
_FWDT(WDT_OFF); // Watchdog timer disabled
_FBORPOR(PBOR_OFF & MCLR_EN); // Brown-out reset disabled, MCLR reset enabled
_FGS(CODE_PROT_OFF); // Code protect disabled




int main()
{
ADPCFG = 0xFFFF ;
TRISB = 0xFFFF ;
LATE = 0xFFFF;
TRISE = 0xFFF0;
int x;
for(x=0;x<100;x++)
{
LATEbits.LATE0 = 1;
delay(21);
LATEbits.LATE0 = 0;
delay(79);
}

}

delay(int d)
{
int i,j;
for(i=0;i<d;i++)
for(j=0;j<250;j++)
Nop();
}

發表於: 2009/11/4 18:12
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